JEE MAIN - Physics (2024 - 6th April Evening Shift - No. 23)
In the given figure an ammeter A consists of a $$240 \Omega$$ coil connected in parallel to a $$10 \Omega$$ shunt. The reading of the ammeter is ________ $$\mathrm{mA}$$.
_6th_April_Evening_Shift_en_23_1.png)
پاسخ دهید
160
توضیح
$$\begin{aligned}
& i=\frac{24}{140 \cdot 4+r_A}=\frac{24}{140 \cdot 4+9 \cdot 6}=0.16 \mathrm{~A} \\
& i=160 \mathrm{~mA}
\end{aligned}$$